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Find the fourth term from the end in an A.P. –11, –8, –5, ..., 49.

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Sol.     –11, –8, –5, ............., 49 is an AP.
           Where a = –11, d = –8 –(–11) = 3
                  tn =  a + (n –1)d
                 49 = –11 + (n –1) 3
         49 + 11 = 3n – 3
                 60 = 3n – 3
                 3n = 63
                   n = 21
        The fourth term from the end is t18
∴      t18 = a + (18 – 1) d
              = –11 + 17 × 3
              = –11 + 51
        t18 = 40

∴     The fourth term from the end is 40

Arithmetic Progression September 28 , 2018 0 Comments 35 views